Puzzle 8N85 Main


Board Thirteen Blues


 by Richard Pavlicek

Bridge tournaments used to run smoothly. Boards were duplicated by people, and scores were hand-written on pickup slips.

Now it’s a circus! Boards are duplicated by machine, and scores are entered into electronic devices.
Never in the history of bridge have there been more fouled boards and scoring errors.

Fortunately, what’s bad for bridge can be good for a bridge puzzle, at least when coupled with a warped mind.
As a case in point, let’s follow Board 13 from the Open Pairs at the Key West Regional.

Sec A Bd 13S A Q J 4WestNorthEastSouth
Both vulH 4 3 21 C1 D1 H
D 3 2Pass1 SPass3 NT
C A Q J 5PassPassPass
S K 10 9 8TableS 7 6 5
H 7 6H K 10 9 8Declarer wins 13 tricks!
D 6 5D K 10 9 8 7
C K 10 9 8 7C 6
S 3 2
H A Q J 5
Lead: D 6D A Q J 4
3 NT SouthC 4 3 2

A finesser’s dream! Declarer wins the diamond cheaply and finesses seven more times to reach S A-4 H 4 C A-5 opposite H A-5 D A-4 C 4. Then he has the option to squeeze either opponent for a 13th trick; red aces squeeze West, or black aces squeeze East. The same finesses also allow 12 tricks in either major, but no 13th of course with a sure trump loser.

So what, you ask? Well, here’s the ‘identical’ board in Section B:

Sec B Bd 13S 4 3 2WestNorthEastSouth
Both vulH A Q J 51 DPass2 C
D A 4 3 2Pass2 HPass3 NT
C Q JPassPassPass
S K 10 9 8TableS 7 6 5
H 7 6H K 10 9 8Declarer is down 2!
D 6 5D K 10 9 8 7
C K 10 9 8 7C 6
S A Q J
H 4 3 2
Lead: D 6D Q J
3 NT SouthC A 5 4 3 2

The East-West hands are the same, but North-South are entirely different, and this time ugly for declarer. Instead of four overtricks, 3 NT is now set two tricks with perfect defense: diamond lead ducked; heart finesse lost to East, then a spade shift and continuations ruin declarer’s communication. Major-suit games fare miserably as well, with 4 H down three, and 4 S down four.

But wait, there’s more!

I was in Section C, and my Board 13 had North-South rearranged again — and remarkably so, as the only makable game was four spades. Alas, I’ve lost the hand record! I wrote the ACBL for another copy, but they disavow any knowledge — not only of this event but in general. Perhaps you can help restore it. There were no void suits; I remember that.

Construct a South hand with which 3 NT and 4 H fail but 4 S makes.

Multiple solutions exist. Tiebreaking goals are for North-South to have the lowest freakness and for South to have the most HCP.

Before reading further, can you pick the winning South hand? 
A. S Q-J H A-Q-J-5-4 D A-4 C A-Q-J-5
B. S Q-J H A-5-4-3-2 D A-Q C A-Q-J-5
C. S Q H A-Q-5-4 D A-Q C A-Q-J-5-4-3
D. S J H A-Q-5-4-3 D A-Q-4 C A-Q-J-5

Quit

Top Board Thirteen Blues

Dan Gheorghiu Wins

This puzzle contest, designated “April 2018” for reference, was open for over a year. Participants were limited to one try, unlike my usual contests that allowed entries to be revised with only the latest one counting. Participation was lean, no doubt a testament to the difficulty of the puzzle. There were six correct solutions, of which two were optimal (least North-South freakness and the most South HCP).

Congratulations to Dan Gheorghiu, who was first to submit the optimal solution. Dan is a brilliant solver with many past wins including The Case of the Four Aces, Third Best Blues, The Nonagon and Reese’s Pieces. Way back in 2011 he also won The Law of Total Trash under the pseudonym “Dan Dang,” which at the time I assumed was his real name, but now it all makes sense… Dang is he good!

Winner List
RankNameLocationFreaknessSouth HCP
1Dan GheorghiuBritish Columbia421
2Konrad MajewskiPoland421
3Jean-Christophe ClementFrance420
4Duncan BellEngland420
5Tim BroekenNetherlands620
6Bob OndoMichigan1021

Puzzle 8N85 MainTop Board Thirteen Blues

Solution

Creating a layout where 3 NT and 4 H both fail yet 4 S makes is quite a task, with few solutions — but that’s what puzzles are made of. Below is one valid solution:

4 S SouthS A Q 4 3 2TrickLead2nd3rd4th
makes 4H J 21. WD 627Q
D J 3 22. SS JKA5
C 4 3 23. NH JKA6
S K 10 9 8 TableS 7 6 54. SH Q728
H 7 6H K 10 9 85. SD A538
D 6 5D K 10 9 8 76. SH 3C 7S 29
C K 10 9 8 7C 67. NS Q6D 48
S J8. NS 37H 49
H A Q 5 4 39. WS 104D 9H 5
Freakness 6D A Q 410. WC 1026J
South 20 HCPC A Q J 511. SC 583D 10
West is endplayed

Four spades is made as shown. If West instead chooses to ruff at Trick 6, a diamond is pitched, and all variations lead to 10 tricks.

Three notrump is defeated with a diamond lead. If declarer next leads a heart to the jack, East wins and shifts to a spade. Declarer now cannot develop a ninth trick without the defense winning five. The same diamond lead also defeats 4 H.

The optimal solution that follows was found only by Dan Gheorghiu and Konrad Majewski:

4 S SouthS A 4 3 2TrickLead2nd3rd4th
makes 4H 3 21. WS KA5J
D Q J 3 22. ND QKA5
C 4 3 23. SD 46J7
S K 10 9 8 TableS 7 6 54. NH 28J6
H 7 6H K 10 9 85. SH A739
D 6 5D K 10 9 8 76. SS Q826
C K 10 9 8 7C 67. SH 4C 7S 310
S Q J8. NS 47H 59
H A Q J 5 49. WS 10D 2D 8H Q
Freakness 4D A 410. WC 1026J
South 21 HCPC A Q J 511. SC 583D 9
West is endplayed

West would hardly lead the S K in practice, but at double-dummy it’s the strongest start — and in fact necessary to beat 4 H, although any spade is sufficient to beat 3 NT. Meanwhile, 4 S cannot be stopped with any defense.

Triskaidekaphobes

Dan Gheorghiu: Insanely hard puzzle!

The Donald: “Only six correct solutions” my ass! Even Hillary sent more than that, and I submitted 13,
making four spades on every one of them. Simple play… trump a loser.

I would agree with an added comma. “Trump, a loser” is the correct form.

Professor Irwin Corey: The feasibility of this construction is an analytical catalyst which
exacerbates protocol over procedure to remain indigenous to its inception.

Puzzle 8N85 MainTop Board Thirteen Blues

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