Puzzle 8K93 Main |
| by Richard Pavlicek |
With spades trump and South declarer, consider the following position with West on lead. Despite a variety of opportunities, with three missing kings offside declarer can win only four tricks. You can trust me on this, as I have shown it to everyone in my psycho ward, and they all agree: With best defense declarers maximum is four.
Quoth the ravin lunatics: Never more.
trump | A J 2 | Trick | Lead | 2nd | 3rd | 4th | |
West leads | 4 3 | 1. W | J | K | A | Q | |
A 3 2 | 2. E | 10! | 4 | 9! | 2 | ||
K | 3. E | J! | |||||
| K 4 | ||||||
K 10 9 7 | J 8 | ||||||
K J 9 6 | 10 8 7 | ||||||
J | A 4 | ||||||
Q 3 | |||||||
A Q 2 | |||||||
N-S can win | Q 5 4 | ||||||
4 tricks | Q |
After the obvious club lead, East must shift to the 10, and if declarer smartly ducks as shown, West must play the nine to avoid being endplayed later; then East must abandon diamonds and shift to a heart. This defense frustrates declarer, who can win only his two natural trump tricks and two side aces. Never more.
Your job is to make the N disappear to become Ever more.
Rearrange the North-South cards so declarer can win more tricks.
The main goal is to win the most tricks, which must be winnable against any lead and any defense. A further goal is to divide the North-South HCP and spot-card (2,3,4,5) totals as evenly as possible. Try it yourself before reading the winning solutions below.
Congratulations to Grant Peacock, Maryland, who was the first of eight solvers to submit the ideal solution, not only to win nine tricks but to divide the HCP and spot cards evenly. How fitting! Being a Baltimore Ravens fan makes his win Poe-litically correct. Grant is a longtime contributor, also winning my Keep the Ship Afloat play contest (April 2002) with a whopping 687 participants.
Rank | Name | Location | Tricks | HCP | Spots |
---|---|---|---|---|---|
1 | Grant Peacock | Maryland | 9 | 12-12 | 14-14 |
2 | Tim Broeken | Netherlands | 9 | 12-12 | 14-14 |
3 | Tom Slater | England | 9 | 12-12 | 14-14 |
4 | Leigh Matheson | Australia | 9 | 12-12 | 14-14 |
5 | Jean-Christophe Clement | France | 9 | 12-12 | 14-14 |
6 | Jamie Pearson | Ontario | 9 | 12-12 | 14-14 |
7 | Nicholas Greer | England | 9 | 12-12 | 14-14 |
8 | Dan Gheorghiu | British Columbia | 9 | 12-12 | 14-14 |
9 | Jon Greiman | Illinois | 9 | 13-11 | 12-16 |
10 | Charles Blair | Illinois | 9 | 13-11 | 12-16 |
11 | Jim Munday | Mississippi | 9 | 13-11 | 12-16 |
12 | Peter Boyd | Maryland | 9 | 15-9 | 14-14 |
13 | Gareth Birdsall | England | 9 | 15-9 | 14-14 |
14 | Paul Blume | Florida | 9 | 17-7 | 10-18 |
15 | Michal Stefanow | England | 9 | 17-7 | 6-22 |
16 | Dan Baker | Texas | 9 | 18-6 | 9-19 |
Puzzle 8K93 Main | Top Ever More |
As the 16 correct solvers showed, it is possible to win all nine tricks with a favorable layout of the North-South cards. Obviously this must include a club void, and the A behind the king. A straightforward solution is to give North the A-Q in both red suits, as shown below.
trump | 3 | Trick | Lead | 2nd | 3rd | 4th | |
West leads | A Q 4 | 1. W | 6 | Q | 7 | 2 | |
A Q 5 | 2. N | K | A | 2 | J | ||
K Q | 3. S | 2 | 7 | Q | 8 | ||
| K 4 | 4. N | 3 | 4 | Q | 9 | |
K 10 9 7 | J 8 | Win the rest | |||||
K J 9 6 | 10 8 7 | ||||||
J | A 4 | ||||||
A Q J 2 | |||||||
3 2 | |||||||
4 3 2 | |||||||
N-S win all | |
After ruffing out the A, draw trumps and claim. Unfortunately this comes no where near an even HCP split (17-7). One improvement (15-9) is to give South the Q, which loses the finessable trick but gains it back when West is eventually squeezed in the red suits.
Before showing the optimal solution, lets look at this one submitted by three solvers (places 9-11). Splitting the HCP 13-11 is only one off the mark, and the play has a neat denouement.
trump | 3 | Trick | Lead | 2nd | 3rd | 4th | |
West leads | Q 4 3 2 | 1. W | 6 | Q | 7 | 2 | |
A Q | 2. N | K | A | 2 | J | ||
K Q | 3. S | A | 7 | 2 | 8 | ||
| K 4 | 4. S | 3 | 9 | A | 8 | |
K 10 9 7 | J 8 | 5. N | Q | 4 | 4 | 9 | |
K J 9 6 | 10 8 7 | 6. N | 3 | J | J | 10 | |
J | A 4 | 7. S | 5 | J | 3 | 10 | |
A Q J 2 | Win the rest | ||||||
A | |||||||
5 4 3 2 | |||||||
N-S win all | |
No defense matters, so suppose West leads a diamond to attack dummys entries. Win cheaply, ruff out the A, unblock the A, cross in diamonds, discard a diamond on the good club, ruff a heart, and ruff your last diamond in dummy. The last two tricks then have South poised with A-Q over Easts K-4 for a trump coup.
Eight solvers found the ideal solution, which is unique for distributional pattern and HCP placement. Spot cards allow some slight variations: The 2 and 3 can be swapped if compensated by swapping the 2 and 3, or the 4 and 5. The layout also requires two distinct play techniques, depending on whether West leads a club or a heart.
trump | J 2 | Trick | Lead | 2nd | 3rd | 4th | |
West leads | A Q 4 3 | 1. W | J | Q | A | 3 | |
5 | 2. S | A | 6 | 5 | 7 | ||
K Q | 3. S | 2 | 9 | 2 | 8 | ||
| K 4 | 4. N | K | 4 | 3 | 7 | |
K 10 9 7 | J 8 | 5. N | J | 4 | Q | J | |
K J 9 6 | 10 8 7 | 6. S | A! | ? | |||
J | A 4 | West is squeezed | |||||
A Q 3 | |||||||
2 | |||||||
A Q 4 3 2 | |||||||
N-S win all | |
Leigh Matheson: On a club lead, take the ruffing club finesse; ruff one diamond, cash the club winner, then finesse and draw trumps to squeeze West.
Nicholas Greer: On a club lead, ruffing one diamond leads to a red-suit squeeze against West.
Jamie Pearson: It took me a long time to get that A-Q into the South hand! At first I was trying to put clubs in South for ruffs, but the entries just didnt work.
Now suppose West leads a heart:
trump | J 2 | Trick | Lead | 2nd | 3rd | 4th | |
West leads | A Q 4 3 | 1. W | 10 | Q | 8 | 2 | |
5 | 2. N | A | J | 2 | 7 | ||
K Q | 3. N | 5 | 7 | A | 6 | ||
| K 4 | 4. S | 3 | 9 | 2 | 8 | |
K 10 9 7 | J 8 | 5. N | K | A | 3 | J | |
K J 9 6 | 10 8 7 | 6. S | 4 | J | J | 10 | |
J | A 4 | 7. N | Q | 4 | Q | 9 | |
A Q 3 | East is trump-couped | ||||||
2 | |||||||
A Q 4 3 2 | |||||||
N-S win all | |
Leigh Matheson: On a heart lead, ruff a diamond, ruff out the A, ruff another diamond, cash winners, then trump-coup East.
Tom Slater: A heart lead is trickier, but I can ruff two diamonds and establish four side winners, then finish with a trump coup. (I found some near solutions with North having both red tenaces to length and a club void, but West always had one killing lead.)
Tim Broeken: Sorry, no Hitchcockian knack this time, as I am pretty sure this is your intended solution.
Charles Blair: I was disappointed that, in Murders in the Rue Morgue, Poe wrote that an astute whist player would attentively study his partners countenance.
Active ethics evidently were not a big thing back then. Of course nobody would ever question Poes integrity, because being cheated was better than being dismembered.
And finally, ravens have a close feathered friend in Grant Peacock, who submitted this verse:
Deep in-to this puzzle peering; long I sit here pleading, fearing.
Wondering why this hellish chore. Might I swap the queen and four?
Finesses, squeezes, one more ruff? Doth a coup bring tricks enough?
Taunt us, Richard, oer and oer. Might this fetch a winning score?
Quoth the solvers, Never more!
Puzzle 8K93 Main | Top Ever More |
© 2015 Richard Pavlicek