Puzzle 8N99 by Richard Pavlicek
This puzzle was inspired by an article by Jim Munday, published on Bridge Winners. I only mention this because Mr. Munday is dedicated to Sue, and he might sue me as well not that I worry about losing the case, but PavCo attorneys have their hands full. Current litigation even disputes my rights to Munday, Munday
so good to me! but I swear its original. Bah-da
bah-da-da-da. Cant trust that day!In fact, to trust anyone resembling a warrants a brain scan.Every other day of the week is fine, yeah
but on a Munday? Better do a cat scan.
Click for a list of successful solvers
Suppose North-South reach 4 on the following layout. Children may be reading this, so Ill spare you the bidding. Suffice it to say it was hardly mundane but certainly mundayne.
West begins by cashing two top hearts as East high-lows to show a doubleton. On the third heart, East has a choice of deuce discards in three suits, but only the 2 allows the contract to be set. Yes, any club but the king would do, but were talking deuces here. If you need a refresher, think Munday from Mississippi. Now that you have a better understanding of deuces, East parts with the correct one, and West exits safely with a trump. Declarer has no successful path to a 10th trick.
Discarding the 2 would allow declarer an easy make by establishing dummys fourth diamond.
Discarding the 2, better known as ruffing, may seem innocuous; but East just spent his one safe exit. His only hope would be to lead the 10 or 9; queen, king, ace; but declarer now can establish a diamond trick by running the 8 on the third round.
What about other North-South layouts? Is a club discard by East always adequate? Obviously, it could never be necessary for East to pitch a diamond, as a club would have to be equivalent. But what about the 2?
Now its your turn to be a Munday morning quarterback:
Construct a South hand where East must ruff the third heart to defeat 4 .
Multiple solutions exist. Tiebreaking goal is for the South hand to be as weak as possible. Weakness is judged by the sum of all card ranks: Ace = 14, king = 13, queen = 12, jack = 11, etc.
If desired, you may submit your solution using the form below. This may be done only once, and doing so will add your name to the list of successful solvers, ranked according to the tiebreaker. You will also receive an automatic reply with a copy of your solution and what Richard believes is the optimal solution.
Acknowledgments to Papa John Phillips (1935-2001)and a gold Zero Tolerance medal to Sue Munday© 2018 Richard Pavlicek