Puzzle 8N79   Main


Bridge with the Abbott


  by Richard Pavlicek

In my continued efforts to stop David Bird from stealing my titles, I remind him that spelling counts. One ‘t’ doesn’t cut it; anyone with half a brain knows there are two, and I could claim three in “Hey Abb-b-o-t-tt.” And don’t think for a minute that adding ‘Monsignors’ to your stories changes anything! My attorneys have issued a cease-and-desist order, so be warned. Keep your beak off my puzzles! If these thefts continue, you may be the next Birdman of Alcatraz.

While surfing the Internet I came across the transcript of a 1938 radio broadcast from San Francisco — just a stone’s throw from Alcatraz, so pay attention, Mr. Bird. It was a half-hour comedy show featuring Abbott and Costello. About midway through my interest was piqued by the following dialog, highlighting Bud Abbott’s penchant for bridge:

[Bud] Lou! Let me give you a hand.

[Lou] No need to clap; we’re friends.

No, you nitwit, I mean a bridge hand.

Thanks! I get nervous on the Golden Gate.

You hold S A-J-10 H K-J-10 D 10-7-5-3 C 10-9-2.

That’s too heavy. I can’t even hold my breath.

What do you lead against six notrump?

First a right cross, then an uppercut.

No, no… which Card do you lead?

Diners Club is all I have.

Never mind. It was cold.

I knew that!

Scribbled in Abbott’s handwriting in the margin was a Yarborough, presumably partner of the above. Beneath it was the note “no long suit in dummy, no accidents,” but that was it. No other bridge information existed, though one could surmise that whatever the missing hands were, Lou would be the perfect dummy. A partial construction shows:

6 NT South  ?
 ?
 ?
 ?
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4
West leads  ?
 ?
 ?
 ?

Having occurred some 80 years ago, and with all parties long passed, hopes of further recovery are slim. Aside from Abbott’s allusion to 6 NT being cold and his curious note, which I’ll interpret as “no 5+ card suit in dummy, and no singleton or void anywhere,” the actual deal may be lost for eternity. Unless… unless… you can help restore this piece of history.

Construct a South hand with which 6 NT can be made against any defense.

Many solutions exist. Because Abbott loved high cards (and the dummy Costello couldn’t tell an ace from a deuce) tiebreaking goal is to make the South hand as strong as possible, first by HCP, and secondarily by the sum of all card ranks.


6 NT South North will
get what
remains

 
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4
Available cards:
West leads S   
H   
D   
C   
S K Q 9 7 5 2
H A Q 6 5 4 2
D A K Q J 6 4 2
C A K Q J 7 5 3



To see if your solution is successful click

Duncan Bell Wins

This puzzle contest, designated “March 2018” for reference, was open for over a year. Participants were limited to one try, unlike my usual contests allowing entries to be revised with only the last one counting. Participation was abundant, of which 37 solutions were correct. Tiebreakers were (1) most South HCP, (2) greatest South rank sum, and (3) earliest date-time of submission, in that order of priority.

Congratulations to Duncan Bell, who was first of six solvers to submit the optimal solution (South with 29 HCP and 153 rank sum). Duncan’s victory is no surprise, having previously won The Twelve of Spades, Just Another Zero and High Stakes Rubber, besides regular high placings when he didn’t win.

Winner List
RankNameLocationSouth HCPSouth Sum
1Duncan BellEngland29153
2Martin VodickaSlovakia29153
3Dan GheorghiuBritish Columbia29153
4Konrad MajewskiPoland29153
5Tim BroekenNetherlands29153
6Jean-Christophe ClementFrance29153
7Nigel GuthrieScotland29152
8Gordon HoScotland29152
9Samuel PahkMassachusetts29152
10Alessandro RapuanoItaly29151
11Tom SlaterEngland28151
12Eric LanierWisconsin28151
13Jacco HopNetherlands28151
14Gonzalo GodedSpain28151
15Walter LeeHong Kong28151
16Foster TomBritish Columbia28151
17Eddy ChoiHong Kong28150
18Leif-Erik StabellZimbabwe28150
19Sherman YuenSingapore28150
20Radu VasilescuPennsylvania28150
21Franco BaseggioNew York28150
22Carl Heinz RosenthalAustria28150
23Charles BlairIllinois28148
24Gareth BirdsallEngland28148
25Nicholas GreerEngland27150
26Ryou NijiMichigan27150
27Ufuk CotukEngland27149
28Richard SteinWashington26149
29Nao TabataFrance26144
30Joe LafortuneConnecticut26144
31Joe ClarkEngland26143
32Harrison LubaMassachusetts25147
33Meelis TiitsonEstonia25143
34Bob OndoMichigan25143
35Levi KatrielCalifornia25143
36Mark RaphaelsonFlorida25142
37Thijs EngberinkNetherlands25140

Puzzle 8N79   MainTop   Bridge with the Abbott

Solution

The most common theme of successful solvers is represented by this construction:

6 NT South S Q 7 5 2
H 6 5 4 2
D 4 2
C J 5 3
Trick
1 W
2 S
3 N
4 N
5 S
6 S
7 S
8 S
9 S
10 S
11 S
Lead
C 10
S 9
C J
C 5
C A
D A
D K
D Q
D J
D 6
S K
2nd
3
10
6
8
H 10
3
5
7
10
S J
A
3rd
4
Q
7
K
H 2
2
4
H 4
H 5
S 2
5
4th
Q
3
2
9
S 4
8
9
S 6
H 3
H 7
8
W-L
W1
W2
W3
W4
W5
W6
W7
W8
W9
W10
L1
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4


HCP 28
Sum 150
S K 9
H A Q
D A K Q J 6
C A K Q 7
West is endplayed

Carl Heinz Rosenthal: On a minor-suit lead, win in hand and run the S 9 through West, North covering with the queen; then run both minors to strip-squeeze West. If instead West rises with the S A over South’s nine, simply preserve the C J as an entry to win the S Q.

Curious that Carl includes his middle name… a solution with 57 varieties?


Improving the rank sum to 151 were Tom Slater and seven others:

6 NT South S Q 5 2
H 6 5 4 2
D J 6 4 2
C 5 3
Trick
1 W
2 S
3 S
4 S
5 S
6 N
7 N
8 S
9 S
10 S
11 S
Lead
C 10
D A
D K
D Q
S 7
D J
C 5
C A
C K
C 7
S K
2nd
3
3
5
7
10
S 6
6
9
H 10
S J
A
3rd
4
2
4
6
Q
S 9
Q
H 2
H 4
H 5
5
4th
J
8
9
S 3
4
10
2
8
H 7
H 8
8
W-L
W1
W2
W3
W4
W5
W6
W7
W8
W9
W10
L1
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4


HCP 28
Sum 151
S K 9 7
H A Q
D A K Q
C A K Q J 7
West is endplayed

Unblocking diamonds, followed by a spade to the queen, leads to the same strip-squeeze against West.


Improving the HCP and rank sum a notch were Nigel Guthrie and two others:

6 NT South S 9 5 2
H 6 5 4 2
D 4 2
C Q 7 5 3
Trick
1 W
2 S
3 W
4 S
5 S
6 S
7 S
8 S
9 S
10 S
11 N
Lead
C 10
S K
C 9
D A
D K
D Q
D J
D 6
S Q
C J
C 7
2nd
3
A
5
3
5
7
10
H 10
10
2
S 8
3rd
4
2
6
2
4
H 2
H 4
H 5
5
Q
S 7
4th
K
3
A
8
9
S 4
H 7
H 8
6
8
?
W-L
W1
L1
W2
W3
W4
W5
W6
W7
W8
W9
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4


HCP 29
Sum 152
S K Q 7
H A Q
D A K Q J 6
C A K J
West is squeezed

In this case West can win the first spade to avoid the throw-in; but with clubs 3-3 declarer has 11 tricks, and West is eventually squeezed in the major suits. Note the Vienna coup at Trick 9.

Gordon Ho: The S 9 must be in dummy to execute the squeeze.


The optimal solution, found by our winner Duncan Bell and five others, increased the rank sum to 153.

6 NT South S 9 5 2
H 6 5 4 2
D Q 6 4 2
C 5 3
Trick
1 W
2 S
3 W
4 S
5 S
6 S
7 S
8 S
Lead
D 3
S K
D 5
C A
C K
C Q
C J
S Q
2nd
2
A
4
2
9
10
H 10
10
3rd
8
2
9
3
5
H 2
H 4
5
4th
K
3
A
4
6
8
H 3
4
W-L
W1
L1
W2
W3
W4
W5
W6
W7
S A J 10
H K J 10
D 10 7 5 3
C 10 9 2
Table S 8 6 4 3
H 9 8 7 3
D 9 8
C 8 6 4


HCP 29
Sum 153
S K Q 7
H A Q
D A K J
C A K Q J 7

Dan Gheorghiu: Declarer succeeds with a repeating triple squeeze.

After cashing four clubs and the S Q (Vienna coup) the following ending is reached:

NT win all S 9
H 6 5
D Q 6
C
Trick
9 S
10 S
11 S
Lead
C 7
H A
H Q
2nd
H J
K
?
3rd
H 5
6
4th
H 7
8
W-L
W1
W2
S J
H K J
D 10 7
C
Table S 8 6
H 9 8 7
D
C



S 7
H A Q
D J
C 7

At Trick 9 West is triple-squeezed. Suppose he lets go a heart as shown; the H A then drops the king, and the H Q squeezes him in the pointed suits. If West instead unguarded diamonds, declarer would overtake the D J with the queen; then the D 6 squeezes West in the majors. Similar if West unguarded spades.

Monsignor Moments

The Abbot: What a pathetic attempt to capitalize on my fame! Do you really expect anyone to believe this, when you can’t even spell Abbot correctly?

Brother Xavier: How dare you plagiarize my partner! Mr. Bird will see you in court!

Mark Raphaelson: Who’s on first?

Puzzle 8N79   MainTop   Bridge with the Abbott

Apologies to David Bird, and acknowledgments to
Lou Costello (1906-59) and Bud Abbott (1897-1974)
© 2021 Richard Pavlicek