Puzzle 8M55 Main

When in Doubt

by Richard Pavlicek

Professor Freebid and Timothy Tenace boarded their flight from Chennai after a disappointing finish in the Transnational Teams.

“The cards were stacked against us,” Timothy sighed, “like Board 2 against that hopeless Guadeloupean team. I knew your spade bid was weak, but how could I not double four hearts with a singleton in your suit and all that stuff? Amazingly unlucky, I must say.”

The Professor jotted down their hands from memory on his clipboard:

4 × South ? Trick Lead 2nd 3rd 4th
? 1. W 6
?
?
6 Table K Q J 10 9 8
K J 10 9 6
K J 10 9 8 7
K J 10 9 8 7 6 5
?
?
?
?

“Your double was reasonable but you led like a puppet. Yes, I bid spades, but you have to visualize. With both minors bottled up, how will declarer make tricks? Ruffing, that’s how. I realize you’ll never understand the intricacies of boson deflection theory, but common sense dictates a trump lead. Even the old cliche ‘When in doubt lead trumps’ is more often right than not.”

“But I had a broken sequence,” Timothy argued. “It would usually cost me a trump trick.”

“Cost works both ways,” the Professor explained. “You might win one fewer trump trick, but surely you’ll regain the lead for a second trump lead, and probably again to clear trumps and wipe out all their ruffing power.”

“I suppose,” Timothy reluctantly admitted. “I just hate to lead from a tenace.”

“That’s hard to believe from your name! Have you ever seen me reject a free bid?”

The intercom interrupts: “We are next in line for takeoff. Please turn off all electronic devices, return tray tables to their upright and locked position, and stow all personal items… [10-second pause] …and to the dinosaur in Row 7, this includes clipboards.”

Construct the North-South hands so that only a trump lead will defeat 4 .

A further goal (tie-breaker for the January 2016 contest) is for the South hand to be as strong as possible, judged by the sum of all card ranks: Ace = 14, King = 13, Queen = 12, Jack = 11, etc.

Dean Pokorny Wins

In January 2016 this puzzle was presented as a challenge, inviting anyone who wished to submit a solution. The new year got off to a fair start with 42 persons offering a try, of which the 14 listed produced valid constructions. A diverse crowd from 10 different countries — and thanks to the Peacock for keeping our homeland on the chart.

Congratulations to Dean Pokorny, Croatia, who was the first of five to submit the optimal solution (strongest possible South hand). Dean doesn’t enter very often, but when he does he’s usually spot on. Previous wins include Queens Around in the current series, Dead Man’s Deal in my 2011 series, and a long way back to my play-contest days, Distribution Most Foul with 838 participants. Let’s see… 838/42 means I’ve only faded 20-fold in 12 years. Not bad, as I comfortably avoid division by zero.

Winner List
Rank Name Location South Total
1 Dean Pokorny Croatia 124
2 Tim Broeken Netherlands 124
3 Leif-Erik Stabell Zimbabwe 124
4 Dan Gheorghiu British Columbia 124
5 Marcin Krawczyk Poland 124
6 Jamie Pearson Ontario 116
7 Jean-Christophe Clement France 115
8 Jonathan Mestel England 113
9 Tom Slater England 113
10 Tina Denlee Quebec 111
11 Jurijs Balasovs Latvia 109
12 Grant Peacock Maryland 104
13 Nicholas Greer England 100
14 Gary Leung Hong Kong 100

Winner List
Rank	Name	Location	South Total
1	Dean Pokorny	Croatia	124
2	Tim Broeken	Netherlands	124
3	Leif-Erik Stabell	Zimbabwe	124
4	Dan Gheorghiu	British Columbia	124
5	Marcin Krawczyk	Poland	124
6	Jamie Pearson	Ontario	116
7	Jean-Christophe Clement	France	115
8	Jonathan Mestel	England	113
9	Tom Slater	England	113
10	Tina Denlee	Quebec	111
11	Jurijs Balasovs	Latvia	109
12	Grant Peacock	Maryland	104
13	Nicholas Greer	England	100
14	Gary Leung	Hong Kong	100

Puzzle 8M55 Main Top When in Doubt

Solution

During the contest run, several people inquired if it were necessary for both distinct trump leads ( K and J) to defeat 4 , or if either one would suffice. Grammatically, I think this is answered by the condition stating “only a trump lead,” which would be true if either or both were successful. Curiously, every correct entry but one made no difference which heart was led; either produced the same result. Below is the odd man out, our British Agent 006 (not quite ready for Goldfinger) who earns style points by defeating 4 with only one card:

4 × South 2 Trick Lead 2nd 3rd 4th
Q 5 4 3 2 1. W K! 2 6 A
4 3 2 2. S A 6 2 8
Q 4 3 2 3. S 3 9 2 9
6 Table K Q J 10 9 8 4. W J Q 10 7
K J 10 9 6 5. N 2 5 A 9
K J 10 9 8 7 6. S 4 9 3 J
K J 10 9 8 7 6 5 7. N 3 6 8 10
A 7 5 4 3 8. S 5 10 4 Q
A 8 7 continued below…
A Q 6 5
A

Tom Slater: After a spade lead, declarer cashes the A and begins crossruffing, overruffing if necessary; West gets endplayed and declarer wins six hearts and four side tricks. The J lead looks better, as after winning the Q, declarer cannot overruff in dummy; but by preserving the A entry, he can still make all the low trumps en passant, and depending on West’s defense, produce some sort of squeeze or endplay. Leading specifically the K ruins the timing, as it cuts down the ruffs while removing an entry from South.

In the play shown above, West ruffs in early (optional) to lead a second trump but must not ruff again to reach the ending:

win 3 — Trick Lead 2nd 3rd 4th
5 9. N 5 7 7 10
4 3 10. W K 4 7 5
Q 4 11. W J Q 8 6
— Table K Declarer fails
10 —
K J 8 7
K J 8 7
7
—
A Q 6 5
North leads —

Declarer’s only hope is to exit with a trump, but West simply cashes the K and gives dummy the Q to await the setting trick in diamonds.

Viva la difference!

Another curiosity is that every successful entry had declarer winning 10 tricks with a spade lead, and nine with a trump lead, as minimally required by the puzzle. Except one! The Professor would have reveled in the following layout, with his sage advice hitting a high note: Nine tricks with a trump lead; eleven with anything else. Additional style points to Jamie Pearson for this two-trick differential:

4 × South 4 3 2 Trick Lead 2nd 3rd 4th
7 3 2 1. W 6 2 10 A
Q 6 5 4 3 2 2. S A 9 2 7
2 3. S A 9 2 5
6 Table K Q J 10 9 8 4. S 3 10 2 6
K J 10 9 6 5. N 3 8 4 10
K J 10 9 8 7 6. S 4 J 3 7
K J 10 9 8 7 6 5 7. N 4 6 8 J
A 7 5 8. S Q K 7 8
A Q 8 5 4 9. N 5 8 5 K
A 10. S 5!
A Q 4 3 Declarer wins 11 tricks

Jamie Pearson: On a non-heart lead, win the A, A and A, then crossruff three rounds of clubs and diamonds (overruffing East if needed). Eliminating clubs and diamonds collapses the spade losers into West’s good hearts [so he is endplayed when forced to ruff Trick 10]. With a heart lead only two rounds of crossruffing are possible, and declarer must eventually lose two trumps and two side tricks (West can continue hearts to avoid any endplay).

All points South

For tie-breaking purposes the object was to construct the strongest South hand, and it is possible for South to have all the high cards. Superficially this seems unlikely, particularly in real life, as I digress to reveal the Guadeloupean stars in action. On Board 2 (below) the Professor opened 3 , and South overcalled 3 NT. North correctly judged this contract to be hopeless, so he tried 4 . South was clueless what this meant — natural? Gerber? Stayman? — but guessed to bid 4 , which Timothy whacked. Trust me on this. (I would produce the hand records, except the Guadeloupean court considers me a security threat and won’t release them.)

Each of the five top solvers produced the following optimal layout, identical to every spot card, packing South to the hilt. Watch this magical make after Timothy blindly leads the Professor’s suit.

Marcin Krawczyk: I’m almost sure this solution gives South the highest card-rank sum.

Dan Gheorghiu: Looks like the ultimate card count!

4 × South 4 3 2 Trick Lead 2nd 3rd 4th
7 4 3 2 1. W 6 2 8 A
6 5 4 3 2 2. S A 9 2 5
2 3. S 3 10 2 6
6 Table K Q J 10 9 8 4. N 2 7 A 9
K J 10 9 6 5. S Q! K 3 8
K J 10 9 8 7 6. W J 4 7 5
K J 10 9 8 7 6 5 7. S 4 J 3 8
A 7 5 continued below…
A Q 8 5
A Q
A Q 4 3

Note the key play at Trick 5, exiting in diamonds, rather than depleting dummy of entries with another club ruff. Timothy cannot benefit by leading a trump now (too late) so he exits with a diamond hoping for an uppercut with the 8. Not this time. Declarer ruffs, then ruffs a club to reach this ending:

win 4 4 3 Trick Lead 2nd 3rd 4th
7 4 8. N 5 9 8 10
6 5 9. S Q K 7 10
— 10. N 3 J 5 9
— Table K Q J 10 9 Declarer succeeds
K J 10 9 6
10 —
K —
7 5
A Q 8
—
North leads Q

Ruff a diamond in hand, then ruff a club with the heart seven — a necessary card for North to have, as declarer would fail with 5-4-3-2 in dummy. Finally just exit with a spade. West is obliged to ruff his partner’s trick and is endplayed in trumps.

An original trump lead, of course, spoils the fun and declarer is down one.

Guadeloupean ideas

Jamie Pearson: I’m pretty sure there’s a solution with a slick trump elopement, which would obviously be called a Guadelopement.

The Donald: Count me in this month, as I’m never in doubt, and that’s my lead: I am Trump, you imbecile! Further, by defeating this Guadeloupean team, my immigration policy will be easy to push through Congress. No need to build a wall around Guadeloupe!

Puzzle 8M55 Main Top When in Doubt

4 × South	?		Trick	Lead	2nd	3rd	4th
	?		1. W	6
	?
	?
6		K Q J 10 9 8
K J 10 9		6
K J 10 9		8 7
K J 10 9		8 7 6 5
	?
	?
	?
	?

win 3	—		Trick	Lead	2nd	3rd	4th
	5		9. N	5	7	7	10
	4 3		10. W	K	4	7	5
	Q 4		11. W	J	Q	8	6
—		K		Declarer fails
10		—
K J		8 7
K J		8 7
	7
	—
	A Q 6 5
North leads	—

4 × South	4 3 2		Trick	Lead	2nd	3rd	4th
	7 3 2		1. W	6	2	10	A
	Q 6 5 4 3 2		2. S	A	9	2	7
	2		3. S	A	9	2	5
6		K Q J 10 9 8	4. S	3	10	2	6
K J 10 9		6	5. N	3	8	4	10
K J 10 9		8 7	6. S	4	J	3	7
K J 10 9		8 7 6 5	7. N	4	6	8	J
	A 7 5		8. S	Q	K	7	8
	A Q 8 5 4		9. N	5	8	5	K
	A		10. S	5!
	A Q 4 3			Declarer wins 11 tricks

win 4	4 3		Trick	Lead	2nd	3rd	4th
	7 4		8. N	5	9	8	10
	6 5		9. S	Q	K	7	10
	—		10. N	3	J	5	9
—		K Q J 10 9		Declarer succeeds
K J 10 9		6
10		—
K		—
	7 5
	A Q 8
	—
North leads	Q