Puzzle 7F21 (1994) by Richard Pavlicek

is a Texas transfer to 4
, a relatively easy contract. Wests moronic sacrifice in 5
clearly should have been doubled but then I would have no puzzle so assume North takes the push to 5
.
5
by South
![]() | A 9 7 5 3 2 2 6 5 4 3 A 10 | |
10 8 6 4 5 4 3 Q J 9 8 7 2 | ![]() | Q K J 9 8 7 6 K Q J 9 8 7 |
![]() | K J A Q 10 A 10 2 K 6 5 4 3 |
| West Pass 5 ![]() | North 4 ![]() 5 ![]() | East Dbl All Pass | South 1 NT 4 ![]() |
West leads the
3 (two, king, ace) and your task is to win 11 tricks. Warning: Its tricky!
With 10 routine tricks, the most obvious hope for 11 is to develop some kind of endplay against East based on the heart layout. If you pursue this angle, you will be frustrated by communication pitfalls and the complications of Wests trump holding. Alas, it cant be done.
Can you find the way?

Solution
The key play is to discard the
A on the
Q. Then ruff a heart and return to your hand with the
K. (Optionally, you could ruff the heart at trick two, return to the
K, and then jettison the
A.) Next ruff a club, return to your hand with a trump, and ruff another club. (West cannot gain by ruffing in front of dummy, so assume he discards each time). This leaves the ending shown in the diagram with North to lead:
![]() | A 9 6 5 4 3 | |
10 8 6 Q J 9 | ![]() | J 9 8 K Q 9 |
![]() | J A 10 2 4 3 |
Duck a diamond to East. The forced club or heart return allows you to make all of your trumps separately. The defense is helpless to prevent this.
In all, declarer wins two top hearts, one top diamond, one top club, two high trumps in hand and five ruffs in dummy.

Copyright © 1994 Richard Pavlicek. All rights reserved.