Puzzle 7F19 Main |
| by Richard Pavlicek |
Norths raise to 5
is justified, but Souths final bid seems to be from outer space. The wild stab at 7
appears destined to fail. Even assuming declarer drops Wests singleton
K, there are only 12 tricks. A diamond loser seems inevitable.
But wait! If West leads a low spade, he gives declarer an extra trick. The same is true of a low heart or a low diamond. Further, declarer might be able to develop a squeeze if West finds a safe lead.

| South deals | J | West | North | East | South | |
| None vul | Q | 1
| ||||
K 10 6 4 | 1 ![]() | 5 ![]() | Pass | 7 ?
| ||
Q J 10 9 8 7 6 | Pass | Pass | Pass | |||
Q 9 8 6 4 2 | ![]() | 10 7 3
| ||||
K 10 6 | J 9 7 3 2
| |||||
Q 9 2 | J 7 3
| |||||
K | 3 2
| |||||
A K 5
| ||||||
A 8 5 4
| ||||||
A 8 5
| ||||||
7 South | A 5 4 | |||||
Against this extraterrestrial contract I say, Take me to your leader! What is the only card in Wests hand that will defeat 7
against any play by declarer?
| Puzzle 7F19 Main | ![]() | Top Take Me To Your Leader! |
SolutionFirst lets see how declarer is able to make his contract on a squeeze. Suppose West leads the
K (declarer will drop it anyway). Win the
A and lead two more rounds of trumps (optional).
7 South | J | Trick | Lead | 2nd | 3rd | 4th | |
Q | 1. W | K? | 6 | 2 | A | ||
K 10 6 4 | 2. S | 4 | 2 | Q | 3 | ||
Q J 10 9 8 7 6 | 3. N | J | 2 | 5 | 4
| ||
Q 9 8 6 4 2 | ![]() | 10 7 3 | 4. N | Q | 3 | A | 6 |
K 10 6 | J 9 7 3 2 | 5. S | 4 | 10 | 7 | 7 | |
Q 9 2 | J 7 3 | 6. N | J | 3 | A | 6 | |
K | 3 2 | 7. S | K | 8 | 4 | 7 | |
A K 5 | 8. S | 5 | K | 8 | 9 | ||
A 8 5 4 | continued below | ||||||
A 8 5
| |||||||
A 5 4 | |||||||
Next lead the
Q to the ace and ruff a heart; lead the
J to the ace, cash the
K and ruff another heart to reach the ending below:

win all | | Trick | Lead | 2nd | 3rd | 4th | |
| North leads | | 9. N | 10 | 3 | 5 | 9
| |
K 10 6 | 10. N | 9 | ? | ||||
10 9 | Declarer succeeds | ||||||
Q 9 | ![]() | 10
| |||||
| J
| ||||||
Q 9 2 | J 7 3
| ||||||
|
| ||||||
5
| |||||||
8
| |||||||
A 8 5
| |||||||
| |||||||
The
10 lead from dummy puts East under pressure. A heart discard loses immediately, so assume East lets go his spade; South throws a diamond, and West throws a spade. Now the
9 effects a double squeeze: East must pitch a diamond; South throws his now useless heart, then West is squeezed.
Variation: If East keeps the
10 and lets go a diamond, the next club squeezes him again. If he throws a spade, West is squeezed in spades and diamonds; if he throws another diamond, the
A drops his jack and West can be finessed.
Yes. First thoughts might turn to the
Q (crushing the jack) or the
K (crushing the queen) but these are red herrings that do nothing to prevent the squeeze.
The squeeze position requires a twin entry in diamonds, which West can erase by leading that suit; but which diamond? A low diamond is obviously disastrous; dummy plays low and declarer can pick up the entire suit. What about the queen? Better, but still failing; declarer can win the
K, ruff hearts twice as before, then squeeze East in the red suits.
The only lead to defeat 7
is the diamond nine. This delicately holds the diamond position, and declarer cannot benefit. Try it.
| Puzzle 7F19 Main | ![]() | Top Take Me To Your Leader! |
© 1994 Richard Pavlicek