Puzzle 7F18 (1994) by Richard Pavlicek

. Or at least give it a try before you look at the answer.
7
by South
![]() | Q 5 2 Q 6 3 A K J 9 8 A 4 | |
J 7 6 9 8 7 7 3 Q J 10 6 5 | ![]() | K 4 3 5 2 10 6 5 4 2 9 8 7 |
Lead: Q | A 10 9 8 A K J 10 4 Q K 3 2 |
| West Pass Pass Pass All Pass | North 1 NT 2 ![]() 4 ![]() 5 ![]() | East Pass Pass Pass Pass | South 2 ![]() 3 ![]() 4 NT 7 ![]() |
At first it looks easy. Declarer has 12 top tricks five hearts, four diamonds, two clubs and a spade plus he can ruff a low club in dummy for 13. Not true! If you ruff a club, you will be unable to win four diamond tricks because the suit is blocked.
Since declarer has 12 tricks (either in high cards or by ruffing a club at the expense of a diamond trick), the first thought would be some kind of squeeze play. Perhaps East can be squeezed since he holds the
K and a diamond stopper. No, East will discard after the dummy and it will not work.
Take it from there.

Solution
5 appears to be insignificant opposite Souths 10-9-8.
Win the
K and cash the
K and
J (any two trumps are OK as long as you save the queen). Next lead the
Q and overtake with the king. Lead the
9, East covers with the 10 and you ruff. (If East did not cover, discard a spade and ruff the
8 with the
10.)
Cash the
A (key play) then cross to dummy with the
Q to win the rest of the diamonds. When North leads his last diamond this is the ending:
![]() | Q 5 A A | |
J 7 J 10 | ![]() | K 4 9 8 |
![]() | 10 A 3 2 |
East must throw a club (else his
K ruffs out), South throws his last spade, and West is also squeezed. If he throws a spade, Norths queen can be led through East to smother the jack and establish the five. So West also throws a club. Now the
A is cashed and South is able to win the last trick with the
3 (or more poetically with the carefully preserved
2).

Copyright © 1994 Richard Pavlicek. All rights reserved.