Puzzle 7F14 (1993) by Richard Pavlicek

3 NT by South
![]() | K 3 2 A 6 5 4 K 3 2 A 5 4 | |
Q J 10 9 8 7 Q J 10 9 8 7 6 | ![]() | 8 7 Q J 10 9 7 6 Q J 10 9 8 |
![]() | A 6 5 4 K 3 2 A 5 4 K 3 2 |
The problem is: Can declarer develop a ninth trick against any defense? Clearly, this must result from some kind of squeeze position, so the problem could also be stated: Can declarer develop a successful squeeze against East or West?

Solution
(1) a diamond, heart or spade, win the
A,
K and
K (in any order), then duck a heart to East. If East returns, say, a club, win the king then concede another heart to East (cashing the
A is optional). A club is ducked, and West is finally squeezed in spades and diamonds.
(2) a club (best), win the king. Cash the
K (optional), then duck a heart to East. East now has the privilege (or should I say predicament) of deciding which of the defenders will become squeezed. Thus, if East returns:
(a) a diamond or heart, win the
A and
K, then concede another heart to East (cashing the
A is optional). A club is ducked, and West becomes the squeeze victim as in variation 1.
(b) a club, win the ace, cash the
K (optional), then concede a spade to West (cashing the
A is optional). A diamond is ducked, and East is finally squeezed in hearts and clubs.
What about a different opening lead? If West leads a spade, declarer ducks and the play follows one of the above variations except that declarer cashes the
K on his own.
If West leads a club or a heart originally, the play (like the deal) is completely symmetrical with East interchanged with West, clubs with diamonds, and hearts with spades.

Copyright © 1993 Richard Pavlicek. All rights reserved.