Puzzle 7F12 (1993) by Richard Pavlicek

6
by South
![]() | A K 5 4 K 2 A 5 4 3 A 3 2 | |
J 10 9 Q 4 3 Q J 10 9 J 10 9 | ![]() | 8 7 6 A K 8 7 6 Q 8 7 6 5 |
Lead: Q | Q 3 2 J 10 9 8 7 6 5 2 K 4 |
It would be sweet if West would cover an honor with an honor when you lead the
J, but you know he will play low.
How can 6
be made?

Solution
A and capture Wests queen with a rare technique known as a smother play.
Win the
A and ruff a diamond; cross to the
A and ruff another diamond; cross to the
K and ruff the last diamond. Next play the
K,
A, ruff a club and cash the
Q to reach the ending shown in the diagram:
![]() | 5 K 2 | |
Q 4 3 | ![]() | A 8 7 |
![]() | J 10 9 |
Lead the
J (West does not cover) to Easts ace. The forced club return allows you to ruff with the 10 and capture Wests queen no matter what he does. If he overruffs, North overruffs with the king; if he underruffs, North discards a spade.
Do you see how to defeat the slam? West has to lead a trump on the opening lead! Bridge can be a crazy game sometimes.

Copyright © 1993 Richard Pavlicek. All rights reserved.