Puzzle 7E75 Main |
| by Richard Pavlicek |
You may not approve of the bidding, but there you, in a grand slam with 12 tricks. Where there are 12, there are usually 13 or so say the squeeze experts. Certainly there are excellent squeeze chances here:
![]() | A 4 2 | West | North | East | South | ||
A 7 5 2 | 1 ![]() | Pass | 1
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A K Q J 10 | Pass | 2 ![]() | Pass | 3
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6 | Pass | 3 ![]() | Pass | 4 NT | |||
![]() | Pass | 5 ![]() | Pass | 5 NT | |||
Lead: 9 | Pass | 7 ![]() | Pass | 7 NT | |||
| All Pass | |||||||
K 8 7 5
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K 4 3
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4 2
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| 7 NT South | A K Q 8 | ||||||
West leads the
9, and 7 NT cannot be made. The following conditions exist:
1. At least one defender has a singleton.
2. West has exactly two even spot cards.
3. The sum of Wests club spots equals the sum of Easts spade spots.
Note: Spot cards are deuce through 10
What are the East-West hands?
SolutionFor starters, both majors must split 3-3. If not, declarer would have a positional major-suit threat behind at least one defender, allowing 7 NT to be made on a compound squeeze. (To understand this, see my article on Pure Squeezes.) For the same reason, East cannot hold five or more clubs. So West cannot have a club singleton; nor East a diamond singleton (East will have too many clubs); nor East a club singleton (hell have at most 12 cards). Therefore, the
9 lead must be the singleton, giving West 3=3=1=6 shape, and East 3=3=5=2.
If West has only one even club spot, his minimum club-spot count is 26 (J-9-7-5-3-2); whereas, Easts maximum spade-spot count is 25 (10-9-6). Therefore, West has two even club spots; and East has all the even major-suit spots (
10-6
10-8-6). Easts third spade must be the nine, else his spade-spot count could never be great enough to equal Wests club-spot count. The only West club holding with a spot total of 25 is J-9-7-4-3-2. So the full deal must be:
| 7 NT South | A 4 2 | Trick | Lead | 2nd | 3rd | 4th | |
| only layout | A 7 5 2 | 1. W | 9
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A K Q J 10 | Win 12 tricks | ||||||
6
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Q J 3 | ![]() | 10 9 6
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Q J 9 | 10 8 6
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9 | 8 7 6 5 3
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J 9 7 4 3 2 | 10 5
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K 8 7 5
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K 4 3
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4 2
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| Down 1 | A K Q 8 | ||||||
And as most people would surely agree: Who really cares!
| Puzzle 7E75 Main | ![]() | Top No Squeeze |
© 1979 Richard Pavlicek