Puzzle 8Q59 Main


Crooked Swiss


 by Richard Pavlicek

Once a month I run a Swiss team game in our ward, which is quite a challenge. With all the subterfuge and unethical behavior, I get many director calls, for which I seldom need a rule book but only a formidable presence to inhibit fist fights. On the first round of our February game, a bellowing “DI—REC—TOR” call came from Herman’s table.

Board 25S 4WestNorthEastSouth
E-W vulH A K Q 7ClydeSharkoRoccoHerman
D A 10 8 6 31 D1 S!1 NT
C A J 92 S3 SDbl!3 NT
S A 10 8 7 6 5TableS Q 2PassPassPass
H 9 8 2H 6 5 3
D 5 4 2D Q J 9
C 4C K Q 10 8 3
S K J 9 3
H J 10 4
3 NT SouthD K 7
West leadsC 7 6 5 2

I rushed to the table to find Herman was livid.

“You won’t believe these animals!” exclaimed Herman. “Rocco overcalls a spade on a doubleton vulnerable, and then doubles my partner’s cue-bid for the lead. Not only does Clyde make a wimpy raise to just two spades, but against three notrump he leads his singleton club, which was the only lead to set me! They have to be cheating, and I demand a score adjustment.”

“I forgot the contract,” Clyde explained, “and was trying for a ruff.”

“Of course!” confirmed Rocco. “My partner is very forgetful at times.”

“Yeah, sure,” countered Sharko, “and I say Clyde is a lying piece of…”

“Whoa!” I broke in quickly. “Let’s all calm down. Everyone knows that Rocco is a chronic psycher, so his bids and doubles don’t mean much, and Clyde may be telling the truth. Therefore, I must let the result stand.”

“Thank you,” acknowledged Rocco, “and while you’re here, the real cheater at this table is Sharko! He shuffled and dealt two boards, 22 and 25, and ends up with a very strong hand on both. Coincidence? I don’t think so. He is stacking the deck!”

Deja vu, I thought to myself, as I’ve heard this complaint before. “There is no proof of your allegation against Sharko, but you may be on to something. I’ll think about it.” When the round finished, I made an announcement over the loudspeaker, “Find your places please for Round 2! And if you play against Sharko, don’t let him make any boards!”

After publishing this story, I received a stern warning from the FCC (Federal Communications Commission) about fair journalism. Because my players are borderline crazy, I must offer equal time to someone with ‘borderline’ removed. So be it:

Tina Denlee: When I sat South, the bidding went 2 C (strong) Dbl (clubs) 2 D (relay) 2 S! … Then on a takeout double, I just could not sit and bid the ill-fated 3NT… But wait! West leads East’s suit; the C 10 wins then C K ducked (count rectification) and C 3 won in dummy, West pitching spades. Next the S 4 queen-king-ace, and West returns a diamond won in dummy (key play). Then four rounds of hearts (pitching the club) pseudo-squeeze West, who erroneously discards one of his ‘idle’ diamonds. Now D K, S 3! West is endplayed and concedes the contract. What a save!

Puzzle time! Suppose Sharko stacks the deck to deal himself three aces and a king, and the remaining 48 cards are distributed at random. For the stacked deals, test your analytic ability by answering two questions:

1. What would be Sharko’s average (mean) number of HCP?
  18.67 18.75 19.12 19.33 19.69 20.25

2. What would be Sharko’s most common (mode) number of HCP?
  16 17 18 19 20 21

Now forgot about that and consider this: In a seven-board Swiss match, Sharko had all plus scores, and so did his teammates except for one board, yet they lost the match. There were no doubled or redoubled contracts.

3. What was the board number of their minus score?
  4 7 10 11 13 20 23 26

QuitTop Crooked Swiss

Cyrus Hettle Three-peats

For the month of March 2026, this puzzle was presented as a contest with 18 participants from 15 different locations. Thanks to those who entered, and congratulations to Cyrus Hettle (Kentucky) who was the first of seven to answer each question correctly.* This is Cyrus’s third consecutive win, following Freeze Me! and Most Cashing Tricks; and on three other contests entered, his solutions were perfect but not the first received.

*Solvers had to calculate their answers. Multiple choice was only added for this writeup.

This puzzle was more mathematical than bridge related, but anything providing a mental challenge is fair game around here — notwithstanding the old story that a bridge player makes his contract on a finesse, while the mathematician goes down on 50.89-percent squeeze.

The perfect scorers are ranked below by date and time of entry.

Winner List
RankNameLocationQ1Q2Q3
1Cyrus HettleKentucky19.691820
2Jim MundayNew Mexico19.691820
3Tina DenleeQuebec19.691820
4Andrew SpoonerAustralia19.691820
5Charles BlairIllinois19.691820
6Dan BakerTexas19.691829
7Richard SteinWashington19.691820

Puzzle 8Q59 MainTop Crooked Swiss

Solutions

1. Average (mean) HCP

Sharko stacks the deck to deal himself three aces and a king (15 HCP) while the remaining 48 cards are distributed at random. What would be Sharko’s average (mean) number of HCP?

An intuitive way to solve this is to consider that 25 HCP must be distributed among 48 slots, 13 of which belong to each other player, and 9 belong to Sharko. Hence, Sharko should average 9/48 of the 25 HCP, or 4.6875 HCP. Adding this to the 15 assured HCP makes 19.6875, or 19.69 rounded. But of course! Nineteen sixty-nine was the year of the moon landing, so it’s all beginning to make sense.

I was skeptical that 19.6875 is the exact answer because of granularity issues (fitting specific high cards into 9 vacant slots versus 13) so I did a complete analysis of every possible high-card arrangement. Stand back!

HCPExtra HCPWaysCombHandsHands × HCPHands w/HCP
15None136c994,143,2801,412,149,20094,143,280
161J436c8121,041,3601,936,661,760121,041,360
171Q436c8121,041,3602,057,703,120171,127,440
2J636c750,086,080851,463,360
181K336c890,781,0201,634,058,360232,135,068
1Q 1J1636c7133,562,8802,404,131,840
3J436c67,791,168140,241,024
191A136c830,260,340574,946,460227,642,580
2Q636c750,086,080951,635,520
1K 1J1236c7100,172,1601,903,271,040
1Q 2J2436c646,747,008888,193,152
4J136c5376,9927,162,848
201K 1Q1236c7100,172,1602,003,443,200221,402,016
1A 1J436c733,390,720667,814,400
2Q 1J2436c646,747,008934,940,160
1K 2J1836c635,060,256701,205,120
1Q 3J1636c56,031,872120,637,440
212K336c725,043,040525,903,840189,736,932
1A 1Q436c733,390,720701,205,120
3Q436c67,791,168163,614,528
1K 1Q 1J4836c693,494,0161,963,374,336
1A 2J636c611,686,752245,421,792
2Q 2J3636c513,571,712285,005,952
1K 3J1236c54,523,90495,001,984
1Q 4J436c4235,6204,948,020
221A 1K336c725,043,040550,946,880150,915,171
1K 2Q1836c635,060,256771,325,632
2K 1J1236c623,373,504514,217,088
1A 1Q 1J1636c631,164,672685,622,784
3Q 1J1636c56,031,872132,701,184
1K 1Q 2J7236c527,143,424597,155,328
1A 3J436c51,507,96833,175,296
2Q 3J2436c41,413,72031,101,840
1K 4J336c4176,7153,887,730
232K 1Q1236c623,373,504537,590,592106,130,745
1A 2Q636c611,686,752268,795,296
1A 1K 1J1236c623,373,504537,590,592
4Q136c5376,9928,670,816
1K 2Q 1J7236c527,143,424624,298,752
2K 2J1836c56,785,856156,074,688
1A 1Q 2J2436c59,047,808208,099,584
3Q 2J2436c41,413,72032,515,560
1K 1Q 3J4836c42,827,44065,031,120
1A 4J136c458,9051,354,815
2Q 4J636c342,840985,320
243K136c61,947,79246,747,00872,221,100
1A 1K 1Q1236c623,373,504560,964,096
1K 3Q1236c54,523,904108,573,696
2K 1Q 1J4836c518,095,616434,294,784
1A 2Q 1J2436c59,047,808217,147,392
1A 1K 2J1836c56,785,856162,860,544
4Q 1J436c4235,6205,654,880
1K 2Q 2J10836c46,361,740152,681,760
2K 3J1236c4706,86016,964,640
1A 1Q 3J1636c4942,48022,619,520
3Q 3J1636c3114,2402,741,760
1K 1Q 4J1236c385,6802,056,320
251A 2K336c65,843,376146,084,40044,246,244
2K 2Q1836c56,785,856169,646,400
3K 1J436c51,507,96837,699,200
1A 3Q436c51,507,96837,699,200
1A 1K 1Q 1J4836c518,095,616452,390,400
1K 3Q 1J4836c42,827,44070,686,000
2K 1Q 2J7236c44,241,160106,029,000
1A 2Q 2J3636c42,120,58053,014,500
1A 1K 3J1236c4706,86017,671,500
4Q 2J636c342,8401,071,000
1K 2Q 3J7236c3514,08012,852,000
2K 4J336c321,420535,500
1A 1Q 4J436c328,560714,000
3Q 4J436c2252063,000
263K 1Q436c51,507,96839,207,16823,836,113
1A 1K 2Q1836c56,785,856176,432,256
1A 2K 1J1236c54,523,904117,621,504
1K 4Q336c4176,7154,594,590
2K 2Q 1J7236c44,241,160110,270,160
3K 2J636c4353,4309,189,180
1A 3Q 1J1636c4942,48024,504,480
1A 1K 1Q 2J7236c44,241,160110,270,160
1K 3Q 2J7236c3514,08013,366,080
2K 1Q 3J4836c3342,7208,910,720
1A 2Q 3J2436c3171,3604,455,360
1A 1K 4J336c321,420556,920
4Q 3J436c2252065,520
1K 2Q 4J1836c211,340294,840
271A 2K 1Q1236c54,523,904122,145,40812,974,655
2K 3Q1236c4706,86019,085,220
3K 1Q 1J1636c4942,48025,446,960
1A 4Q136c458,9051,590,435
1A 1K 2Q 1J7236c44,241,160114,511,320
1A 2K 2J1836c41,060,29028,627,830
1K 4Q 1J1236c385,6802,313,360
2K 2Q 2J10836c3771,12020,820,240
3K 3J436c328,560771,120
1A 3Q 2J2436c3171,3604,626,720
1A 1K 1Q 3J4836c3342,7209,253,440
1K 3Q 3J4836c230,240816,480
2K 1Q 4J1236c27560204,120
1A 2Q 4J636c23780102,060
4Q 4J136c136972
281A 3K136c5376,99210,555,7765,739,564
3K 2Q636c4353,4309,896,040
1A 1K 3Q1236c4706,86019,792,080
1A 2K 1Q 1J4836c42,827,44079,168,320
2K 3Q 1J4836c3342,7209,596,160
3K 1Q 2J2436c3171,3604,798,080
1A 4Q 1J436c328,560799,680
1A 1K 2Q 2J10836c3771,12021,591,360
1A 2K 3J1236c385,6802,399,040
1K 4Q 2J1836c211,340317,520
2K 2Q 3J7236c245,3601,270,080
3K 4J136c263017,640
1A 3Q 3J1636c210,080282,240
1A 1K 1Q 4J1236c27560211,680
1K 3Q 4J1236c143212,096
291A 2K 2Q1836c41,060,29030,748,4102,453,184
1A 3K 1J436c4235,6206,832,980
2K 4Q336c321,420621,180
3K 2Q 1J2436c3171,3604,969,440
1A 1K 3Q 1J4836c3342,7209,938,880
1A 2K 1Q 2J7236c3514,08014,908,320
2K 3Q 2J7236c245,3601,315,440
3K 1Q 3J1636c210,080292,320
1A 4Q 2J636c23780109,620
1A 1K 2Q 3J7236c245,3601,315,440
1A 2K 4J336c2189054,810
1K 4Q 3J1236c143212,528
2K 2Q 4J1836c164818,792
1A 3Q 4J436c11444176
301A 3K 1Q436c4235,6207,068,600951,027
3K 3Q436c328,560856,800
1A 1K 4Q336c321,420642,600
1A 2K 2Q 1J7236c3514,08015,422,400
1A 3K 2J636c342,8401,285,200
2K 4Q 1J1236c27560226,800
3K 2Q 2J3636c222,680680,400
1A 1K 3Q 2J7236c245,3601,360,800
1A 2K 1Q 3J4836c230,240907,200
2K 3Q 3J4836c1172851,840
3K 1Q 4J436c11444320
1A 4Q 3J436c11444320
1A 1K 2Q 4J1836c164819,440
1K 4Q 4J336c0390
311A 2K 3Q1236c385,6802,656,080291,805
1A 3K 1Q 1J1636c3114,2403,541,440
3K 3Q 1J1636c210,080312,480
1A 1K 4Q 1J1236c27560234,360
1A 2K 2Q 2J10836c268,0402,109,240
1A 3K 3J436c2252078,120
2K 4Q 2J1836c164820,088
3K 2Q 3J2436c186426,784
1A 1K 3Q 3J4836c1172853,568
1A 2K 1Q 4J1236c143213,392
2K 3Q 4J1236c012372
1A 4Q 4J136c0131
321A 3K 2Q636c342,8401,370,88093,000
3K 4Q136c263020,160
1A 2K 3Q 1J4836c230,240967,680
1A 3K 1Q 2J2436c215,120483,840
3K 3Q 2J2436c186427,648
1A 1K 4Q 2J1836c164820,736
1A 2K 2Q 3J7236c1259282,944
1A 3K 4J136c1361152
2K 4Q 3J1236c012384
3K 2Q 4J636c06192
1A 1K 3Q 4J1236c012384
331A 2K 4Q336c2189062,37020,368
1A 3K 2Q 1J2436c215,120498,960
3K 4Q 1J436c11444752
1A 2K 3Q 2J7236c1259285,536
1A 3K 1Q 3J1636c157619,008
3K 3Q 3J1636c016528
1A 1K 4Q 3J1236c012396
1A 2K 2Q 4J1836c018594
341A 3K 3Q436c2252085,6804306
1A 2K 4Q 1J1236c143214,688
1A 3K 2Q 2J3636c1129644,064
3K 4Q 2J636c06204
1A 2K 3Q 3J4836c0481632
1A 3K 1Q 4J436c04136
351A 3K 3Q 1J1636c157620,160618
1A 2K 4Q 2J1836c018630
1A 3K 2Q 3J2436c024840
361A 3K 4Q136c136129660
1A 3K 3Q 2J2436c024864
371A 3K 4Q 1J436c041484
Totals 1,677,106,64033,018,036,9751,677,106,640
Average Total HCP / Total Hands = 19.6875

Note that the total number of hands (1,677,106,640) is equal to 48c9 as expected.

Lo and behold, the intuitive answer is indeed exact! A real mathematician evidently knew this:

Dan Baker: Each missing card has a 9/48 chance of being in Sharko’s hand.
By “linearity of expected value,” average HCP = 15 + 25 × 9/48 = 19.6875.

The rounded average could also be found empirically:

Andrew Spooner: I wrote a simulation, but I am not sure whether 19.68 or 19.69 is correct.
It seemed very close, so my tiebreaker was the simple 15 + 25 × 9/48 = 19.6875, or 19.69 rounded.

Richard Stein: I wrote an R simulation for 1 million hands and ran it 10 times…

2. Most Common (mode) HCP

Sharko stacks the deck to deal himself three aces and a king (15 HCP) while the remaining 48 cards are distributed at random. What would be Sharko’s most common (mode) number of HCP?

This was the incongruity that prompted my puzzle. With an average of 19.69 HCP, one would surmise that the most common occurrence would be either 19 or 20 HCP. But no! Surprisingly the mode is 18. As shown by the green box in the table, there are 232,135,068 hands with 18 HCP, while 19 HCP produces only 227,642,580; and 20 HCP even fewer with 221,402,016.

Obviously, the mode of 18 is heavily influenced by the inclusion of one queen and one jack, the most common high-card arrangement, occurring in 133,562,880 hands.

Dan Baker: Most common is 18 HCP with 232,135,068 hands, ahead of 19 with 227,642,580 and 20 with 221,402,016.

Puzzle 8Q59 MainTop Crooked Swiss

3. Board Number of Minus Score

In a seven-board Swiss match, Sharko had all plus scores, and so did his teammates except for one board, yet they lost the match. There were no doubled or redoubled contracts. What was the board number of their minus score?

These solvers explain it as well as I could:

Andrew Spooner: Under the given conditions, the maximum that can be lost on a single board is 19 IMPs (+70, -2220) and the minimum that can be gained is 3 IMPs (+70, +50) except with both sides vulnerable, in which case it is 4 IMPs (+70, +70). Therefore, the match requires a board set in which both vul occurs only once, which is board 20 of set 15-21.

Jim Munday: The 7-board match must be lost 18-19. The most we can lose on a board with one pair plus is 19 IMPs (-2210 with an unsatisfactory +100). To win only 3 IMPs with two plus scores needs at least one side to be nonvul (+70 with +50 setting the nonvul opponents). Board set 15-21 has only one board with both vul (20). I believe this would also apply to board 29.

Indeed it would, though board set 29-35 is rarely used, and my puzzle answer was restricted to 1-28.

Dan Baker: The biggest possible loss is 19 IMPs (small plus vs -2220). With both sides plus, the minimum gain is 3 IMPs with either side nonvul (+50/+50 or +50/+70) else 4 IMPs with both vul (+70/+70). We need only one board with both vul: 20 (in 15-21) and 29 (in 29-35) both work.

Charles Blair: I assume the match used boards 15-21. Otherwise there would be more than one board with both sides vulnerable.

Richard Stein: They played boards 15-21 and lost the crusher on the only board with both vul.

Guilty as Charged

Regarding the complaint against Sharko, I submitted 24 boards he is known to have shuffled and dealt to the IBA (Institute for Bridge Arbitration). Using a detection tool called EDGAR (Extrema Detection Gauge for Asylum Records) they calculated his chance of being honest as 0.0037 percent, which is convincing enough for our purposes. Sharko will not be making any more boards! Nonetheless, his presence in the ward is most welcome for upholding its principles: Everyone’s a crook, so who really cares!

These solvers have been barred from the ward for too many licit activities:

Charles Blair: No doubles and redoubles? I suspect Quaalude abuse in the ward!

Jim Munday: The only thing worse than my statistical acumen is my leads (and bidding?) but I gave it a shot.

And a perfect shot it was! Now if he could only apply this to his leads. (I can vouch that his bidding is incurable.)

Puzzle 8Q59 MainTop Crooked Swiss

© 2026 Richard Pavlicek