Once a month I run a Swiss team game in our ward, which is quite a challenge. With all the subterfuge and unethical behavior, I get many director calls, for which I seldom need a rule book but only a formidable presence to inhibit fist fights. On the first round of our February game, a bellowing DIRECTOR call came from Hermans table.
I rushed to the table to find Herman was livid.
You wont believe these animals! exclaimed Herman. Rocco overcalls a spade on a doubleton vulnerable, and then doubles my partners cue-bid for the lead. Not only does Clyde make a wimpy raise to just two spades, but against three notrump he leads his singleton club, which was the only lead to set me! They have to be cheating, and I demand a score adjustment.
I forgot the contract, Clyde explained, and was trying for a ruff.
Of course! confirmed Rocco. My partner is very forgetful at times.
Yeah, sure, countered Sharko, and I say Clyde is a lying piece of
Whoa! I broke in quickly. Lets all calm down. Everyone knows that Rocco is a chronic psycher, so his bids and doubles dont mean much, and Clyde may be telling the truth. Therefore, I must let the result stand.
Thank you, acknowledged Rocco, and while youre here, the real cheater at this table is Sharko! He shuffled and dealt two boards, 22 and 25, and ends up with a very strong hand on both. Coincidence? I dont think so. He is stacking the deck!
Deja vu, I thought to myself, as Ive heard this complaint before. There is no proof of your allegation against Sharko, but you may be on to something. Ill think about it. When the round finished, I made an announcement over the loudspeaker, Find your places please for Round 2! And if you play against Sharko, dont let him make any boards!
After publishing this story, I received a stern warning from the FCC (Federal Communications Commission) about fair journalism. Because my players are borderline crazy, I must offer equal time to someone with borderline removed. So be it:
Tina Denlee: When I sat South, the bidding went 2 (strong) Dbl (clubs) 2 (relay) 2 ! Then on a takeout double, I just could not sit and bid the ill-fated 3NT But wait! West leads Easts suit; the 10 wins then K ducked (count rectification) and 3 won in dummy, West pitching spades. Next the 4 queen-king-ace, and West returns a diamond won in dummy (key play). Then four rounds of hearts (pitching the club) pseudo-squeeze West, who erroneously discards one of his idle diamonds. Now K, 3! West is endplayed and concedes the contract. What a save!
Puzzle time! Suppose Sharko stacks the deck to deal himself three aces and a king, and the remaining 48 cards are distributed at random. For the stacked deals, test your analytic ability by answering two questions:
1. What would be Sharkos average (mean) number of HCP? 18.67 18.75 19.12 19.33 19.69 20.25
2. What would be Sharkos most common (mode) number of HCP? 16 17 18 19 20 21
Now forgot about that and consider this: In a seven-board Swiss match, Sharko had all plus scores, and so did his teammates except for one board, yet they lost the match. There were no doubled or redoubled contracts.
3. What was the board number of their minus score? 4 7 10 11 13 20 23 26
*Solvers had to calculate their answers. Multiple choice was only added for this writeup.
This puzzle was more mathematical than bridge related, but anything providing a mental challenge is fair game around here notwithstanding the old story that a bridge player makes his contract on a finesse, while the mathematician goes down on 50.89-percent squeeze.
The perfect scorers are ranked below by date and time of entry.
Sharko stacks the deck to deal himself three aces and a king (15 HCP) while the remaining 48 cards are distributed at random. What would be Sharkos average (mean) number of HCP?
An intuitive way to solve this is to consider that 25 HCP must be distributed among 48 slots, 13 of which belong to each other player, and 9 belong to Sharko. Hence, Sharko should average 9/48 of the 25 HCP, or 4.6875 HCP. Adding this to the 15 assured HCP makes 19.6875, or 19.69 rounded. But of course! Nineteen sixty-nine was the year of the moon landing, so its all beginning to make sense.
I was skeptical that 19.6875 is the exact answer because of granularity issues (fitting specific high cards into 9 vacant slots versus 13) so I did a complete analysis of every possible high-card arrangement. Stand back!
Note that the total number of hands (1,677,106,640) is equal to 48c9 as expected.
Lo and behold, the intuitive answer is indeed exact! A real mathematician evidently knew this:
Dan Baker: Each missing card has a 9/48 chance of being in Sharkos hand.By linearity of expected value, average HCP = 15 + 25 × 9/48 = 19.6875.
The rounded average could also be found empirically:
Andrew Spooner: I wrote a simulation, but I am not sure whether 19.68 or 19.69 is correct.It seemed very close, so my tiebreaker was the simple 15 + 25 × 9/48 = 19.6875, or 19.69 rounded.
Richard Stein: I wrote an R simulation for 1 million hands and ran it 10 times
Sharko stacks the deck to deal himself three aces and a king (15 HCP) while the remaining 48 cards are distributed at random. What would be Sharkos most common (mode) number of HCP?
This was the incongruity that prompted my puzzle. With an average of 19.69 HCP, one would surmise that the most common occurrence would be either 19 or 20 HCP. But no! Surprisingly the mode is 18. As shown by the green box in the table, there are 232,135,068 hands with 18 HCP, while 19 HCP produces only 227,642,580; and 20 HCP even fewer with 221,402,016.
Obviously, the mode of 18 is heavily influenced by the inclusion of one queen and one jack, the most common high-card arrangement, occurring in 133,562,880 hands.
Dan Baker: Most common is 18 HCP with 232,135,068 hands, ahead of 19 with 227,642,580 and 20 with 221,402,016.
In a seven-board Swiss match, Sharko had all plus scores, and so did his teammates except for one board, yet they lost the match. There were no doubled or redoubled contracts. What was the board number of their minus score?
These solvers explain it as well as I could:
Andrew Spooner: Under the given conditions, the maximum that can be lost on a single board is 19 IMPs (+70, -2220) and the minimum that can be gained is 3 IMPs (+70, +50) except with both sides vulnerable, in which case it is 4 IMPs (+70, +70). Therefore, the match requires a board set in which both vul occurs only once, which is board 20 of set 15-21.
Jim Munday: The 7-board match must be lost 18-19. The most we can lose on a board with one pair plus is 19 IMPs (-2210 with an unsatisfactory +100). To win only 3 IMPs with two plus scores needs at least one side to be nonvul (+70 with +50 setting the nonvul opponents). Board set 15-21 has only one board with both vul (20). I believe this would also apply to board 29.
Indeed it would, though board set 29-35 is rarely used, and my puzzle answer was restricted to 1-28.
Dan Baker: The biggest possible loss is 19 IMPs (small plus vs -2220). With both sides plus, the minimum gain is 3 IMPs with either side nonvul (+50/+50 or +50/+70) else 4 IMPs with both vul (+70/+70). We need only one board with both vul: 20 (in 15-21) and 29 (in 29-35) both work.
Charles Blair: I assume the match used boards 15-21. Otherwise there would be more than one board with both sides vulnerable.
Richard Stein: They played boards 15-21 and lost the crusher on the only board with both vul.
Regarding the complaint against Sharko, I submitted 24 boards he is known to have shuffled and dealt to the IBA (Institute for Bridge Arbitration). Using a detection tool called EDGAR (Extrema Detection Gauge for Asylum Records) they calculated his chance of being honest as 0.0037 percent, which is convincing enough for our purposes. Sharko will not be making any more boards! Nonetheless, his presence in the ward is most welcome for upholding its principles: Everyones a crook, so who really cares!
These solvers have been barred from the ward for too many licit activities:
Charles Blair: No doubles and redoubles? I suspect Quaalude abuse in the ward!
Jim Munday: The only thing worse than my statistical acumen is my leads (and bidding?) but I gave it a shot.
And a perfect shot it was! Now if he could only apply this to his leads. (I can vouch that his bidding is incurable.)
© 2026 Richard Pavlicek